UPDATE_YEAR
The function UPDATE_YEAR changes the year described by a Date or DateTime into another specified number.
This function takes two pieces of input: a Date or a DateTime, and a Number. It outputs the given Date or DateTime with the year value replaced by the given number.
Declaration
Parameters
datetime (type: DateTime) Any DateTime.
date (type: Date) Any date.
new_year (required, type: Number) The new year; this is the number that will replace whatever value is currently associated with the year in the given Date or DateTime.
Return Values
new_datetime (type: DateTime) The DateTime that results from taking the given DateTime and replacing the year value with the given number.
new_date (type: Date) The Date that results from taking the given Date and replacing the year value with the given number.
Examples
Assume the first example has access to the following DateTime value:
The following example takes the date described in example_date_and_time and replaces the given year value (2021) with 2022. Note that the only difference between the output of this example and example_date_and_time is the the value of the year. When given a DateTime as input, UPDATE_YEAR returns a DateTime:
The above example demonstrates how the UPDATE_YEAR function behaves when given a DateTime as input. In order to further establish how the UPDATE_YEAR function behaves when given a Date as input, assume the last example has access to the following Date value:
The following example takes the Date described in example_date and replaces the given year value (2021) with 2022. Note that the only difference between the output of this example and example_date is the the value of the year. When given a Date as input, UPDATE_YEAR outputs a Date:
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